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=175-16H^2
We move all terms to the left:
-(175-16H^2)=0
We get rid of parentheses
16H^2-175=0
a = 16; b = 0; c = -175;
Δ = b2-4ac
Δ = 02-4·16·(-175)
Δ = 11200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11200}=\sqrt{1600*7}=\sqrt{1600}*\sqrt{7}=40\sqrt{7}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{7}}{2*16}=\frac{0-40\sqrt{7}}{32} =-\frac{40\sqrt{7}}{32} =-\frac{5\sqrt{7}}{4} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{7}}{2*16}=\frac{0+40\sqrt{7}}{32} =\frac{40\sqrt{7}}{32} =\frac{5\sqrt{7}}{4} $
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